pg_field_table

(PHP 5 >= 5.2.0, PHP 7, PHP 8)

pg_field_table — Returns the name or oid of the tables field

说明

pg_field_table(PgSql\Result $result, int $field, bool $oid_only = false): string|int|false

pg_field_table() returns the name of the table that field belongs to, or the table's oid if oid_only is true.

参数

result

An PgSql\Result instance, returned by pg_query(), pg_query_params() or pg_execute()(among others).

field

Field number, starting from 0.

oid_only

By default the tables name that field belongs to is returned but if oid_only is set to true, then the oid will instead be returned.

返回值

On success either the fields table name or oid, 或者在失败时返回 false.

更新日志

版本 说明
8.1.0 The result parameter expects an PgSql\Result instance now; previously, a 资源(resource) was expected.

范例

示例 #1 Getting table information about a field

<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");

$res = pg_query($dbconn, "SELECT bar FROM foo");

echo pg_field_table($res, 0);
echo pg_field_table($res, 0, true);

$res = pg_query($dbconn, "SELECT version()");
var_dump(pg_field_table($res, 0));
?>

以上例程的输出类似于：

foo
14379580

bool(false)

注释

注意:

Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.

参见